In the triangle, bc=12 cm and tan c =0.583. what is the length of the hypotenuse, to the nearest tenth of a centimeter
Accepted Solution
A:
Given that BC=12 cm and tan C=0.583, the value of the hypotenuse will be given as follows: BC is the adjacent, the height AB will be given by AB/BC=tan C thus AB/12=0.583 AB=12*0.583 AB=6.996 hence using Pythagorean theorem: c^2=b^2+a^2 thus; c^2=6.996^2+12^2 c^2=192.944016 c=13.890~14 cm (to the nearest centimeter)