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The solutions to a certain quadratic equation are x = -4 and x = 3. Write the equation in standard f...
4 months ago
Q:
The solutions to a certain quadratic equation are x = -4 and x = 3. Write the equation in standard form below.
Accepted Solution
A:
[tex]y=a(x-x_1)(x-x_2)\\\\x_1=-4;\ x_2=3\ therefore\\\\y=a(x+4)(x-3)\\\\y=a(x^2+x-12)\\\\\boxed{y=ax^2+ax-12a}\ where\ a\in\mathbb{R}-\{0\}[/tex]